lUAS selimut kerucut tersebut adalah...cm².(√=3,14)
Luas permukaan kerucut = phi×r×(r+garis pelukis)
3,14×9×(9+(V9²+40²))
= 28,26×(9+(V81+1.600))
= 28,26×(9+(V1.681))
= 28,26×(9+(41))
= 28,26×50
= 1.413 cm²
Luas selimut kerucut = phi×r×garis pelukis
3,14×9×41
= 1.158,66 cm²
JADIKAN JAWABAN TERCERDAS [answer.2.content]
3,14×9×(9+(V9²+40²))
= 28,26×(9+(V81+1.600))
= 28,26×(9+(V1.681))
= 28,26×(9+(41))
= 28,26×50
= 1.413 cm²
Luas selimut kerucut = phi×r×garis pelukis
3,14×9×41
= 1.158,66 cm²
JADIKAN JAWABAN TERCERDAS [answer.2.content]